Plastic extruder
Power source: electric motor
Power: 15 hp
Shaft speeds: 1750 RPM (N1), 1600 RPM (N2), 400 RPM(N3),
400 RPM(N4)
Shaft diameter (N1)= 1.000 inches
1. A preliminary drive layout in illustrated below. Our
initial drive selection will assume that 1/2” Pitch Rampower is
used.
2. The driving shaft #1 is also the fastest shaft in this example.
We select an initial sprocket size of 21 teeth. From the
sprocket table on page 9, the maximum bore for the 21
tooth sprocket is 1.875” , so this sprocket will accommodate
the 1.000” shaft diameter.
3. Determine the service factor(SF), using the chart on page
14. Under Rubber and Plastics equipment the service factor
for an extruder is 1.5.
Service factor = 1.5
4. Compute the design horsepower(Wd) by multiplying the
power to be transmitted(W) by the service factor.
Wd = W x SF = 15 hp x 1.5 = 22.5 hp
5. Calculate minimum chain width(CW)
Wd = 22.5 hp
V = pZN = (0.5 x 21 x 1750)/12 = 1,531 fpm


6. The nearest larger standard Rampower chain width ,from
page 5, is RPD8406, 1.5 inches wide, with an 8-7-8
assembly.
7. Compute the number of teeth in remaining sprockets:

|