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Drive Selection Example

Plastic extruder
Power source: electric motor
Power: 15 hp
Shaft speeds: 1750 RPM (N1), 1600 RPM (N2), 400 RPM(N3), 400 RPM(N4)
Shaft diameter (N1)= 1.000 inches

1. A preliminary drive layout in illustrated below. Our initial drive selection will assume that 1/2” Pitch Rampower is used.

2. The driving shaft #1 is also the fastest shaft in this example. We select an initial sprocket size of 21 teeth. From the sprocket table on page 9, the maximum bore for the 21 tooth sprocket is 1.875” , so this sprocket will accommodate the 1.000” shaft diameter.

3. Determine the service factor(SF), using the chart on page 14. Under Rubber and Plastics equipment the service factor for an extruder is 1.5.

Service factor = 1.5

4. Compute the design horsepower(Wd) by multiplying the power to be transmitted(W) by the service factor.

Wd = W x SF = 15 hp x 1.5 = 22.5 hp

5. Calculate minimum chain width(CW)

Wd = 22.5 hp
V = pZN = (0.5 x 21 x 1750)/12 = 1,531 fpm

6. The nearest larger standard Rampower chain width ,from page 5, is RPD8406, 1.5 inches wide, with an 8-7-8 assembly.

7. Compute the number of teeth in remaining sprockets:


8. Compute the pitch diameter for each sprocket and construct a final drive layout. The final layout is used to verify that the chain wraps each sprocket by at least 120 degrees and to compute chain length. Wrap and chain length calculations are most easily performed within a CAD program and have been excluded from this illustration.

9. The chain speed of 1531 fpm indicates that either bath or forced feed lubrication should be employed.

Sample Drive Layout